Question 735477
find all solutions to the equations [0,2pie) 
2sin^2x+3sinx+1=0
(2sinx+1)(sinx+1)=0
..
2sinx+1=0
sinx=-1/2
x=7&#960;/6, 11&#960;/6 (in Q3 and Q4 where sin<0)
.. 
sinx+1=0
sinx=-1
x=3&#960;/2

solutions: x=7&#960;/6, 11&#960;/6, 3&#960;/2