Question 735266
The diagonal of a square is 56 centimeters long. Find the perimeter of the square to the nearest tenth.
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let x=side of the square
The diagonal and two of the sides form a right triangle
By the pythagorean theorem, {{{56=sqrt(x^2+x^2)=sqrt(2x^2)=(x)sqrt(2)}}}
{{{x=56/sqrt(2)=39.6}}}
perimeter of the square=4x=158.4 cm