Question 735011
{{{ log( 2,3x ) + log( 2,4 )  = 5 }}}
Make this substitution:
{{{ 5 = log( 2, 32 ) }}}
{{{ log( 2,3x ) + log( 2,4 )  = log( 2,32) }}}
{{{ log( 2, 4*3x )  = log( 2,32 ) }}}
{{{ 12x = 32 }}}
{{{ x = 8/3 }}}
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check:
{{{ log( 2,3*(8/3) ) + log( 2,4 )  = 5 }}}
{{{ log( 2,8 ) + log( 2,4 )  = 5 }}}
{{{ 3 + 2 = 5 }}}
{{{ 5 = 5 }}}
OK