Question 734910
<pre>5<sup>x</sup> = 17

That is equivalent to the equation

x = log<sub>5</sub>17

and you can use the change of base formula to make it

either

x = {{{ln(17)/ln(5)}}}

or

x = {{{log(17)/log(5)}}}  

or you can use a calculator and get

x = 1.760374428

Edwin</pre>