Question 734571
The axis of symmetry and the minimum value give you the vertex, (1, -4) = (h, k).  You can begin developing an equation as {{{y=a(x-1)^2-4}}}.


Could you try to use the given x intercept to solve for and find the value for "a"?  You would then have the equation for this parabola.  Let x=0 and find y.  


How does this work:  x intercept is at -1.
{{{0=a(-1-1)^2-4}}}
{{{0=a*(-2)^2-4}}}
{{{0=4a-4}}}
{{{-4a=-4}}}
{{{a=1}}}.


Parabola is {{{highlight(y=1*(x-1)^2-4)}}}.  y intercept would be at x=0.
{{{y=(0-1)^2-4}}}
{{{y=1-4}}}
{{{highlight(y=-3)}}}.