Question 734575
PROBLEM:(1)
X^2+12X-64=0
(1)FIND COEFFICIENTS A,B,C
A=1,B=12,C=-64
(2)PLUG IN VALUES
X1,2====-B±√B^2-4AC/2A
X1,2====-12±√12^2-4.1.(-64/2.1
(3)SIMPLIFY
X1,2====-12±√400/2
(4)SOLVE FOR X
X1,,=-12±√400/2=4
X2,,=-12√400/2=-16
X=4,-16
PROBLEM(2)
X2-2X-13=0
X=1+√14,,X≈4.7417
X=1-√14,,X≈-2.7417