<PRE><B>Question 734533</B>
{{{7^(1/4) x 49^(-5/8)}}}
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{{{7^(1/4)}} becomes {{{7^(2/8)}}}
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{{{7^2/8)*49^(-5/8)}}}
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we will write 7 as x and 49 as y
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{{{x^(2/8)*49^(-5/8)}}}
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times the ^(2/8) by (-5/8) with an outcome of {{{-5/32}}}
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xy= 7 x 49 = {{{(383)^(-5/32)}}}
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