Question 734335
A calculator isn't going to help you, this is a pure theory problem.<br>

A rule which holds true for -every- statistical distribution is that Var[aX] = a^2*Var[X]. Thus, when you multiply the data set by 38, you multiply its variance by 38^2.<br>

The standard deviation for such a distribution is the square root of the variance, so it'll be sqrt(38^2) = 38 times higher.<br>

PS: If you can access the internet, there are calculators online that'll help you compute standard deviations and the like. Calculating stuff like a standard deviation by hand is a task I'd wish on no one :P