Question 64213
2/5x-1=7/5 
 
To solve this equation one must isolate X, that means to get X on one side of the equation and everything else on the other side.  

1.  Add one to both sides of the equation.  
2/5x -1 +1 = 7/5 +1

2.  Add 7/5 + 1.  
2/5x = 12/5

3.  Divide both sides by 2/5.  
2/5x / 2/5 = 12/5 / 2/5

4.  When you divide 2/5x by 2/5 you get x.  

5.  To divide 12/5 by 2/5 means to multiply by the inverse of the second fraction.  12/5 * 5/2 = 60/10

6.  We are left with X = 60/10  
now reduce the fraction to get 

X = 6


-54/3 + 3/2x + 2

To solve this start by setting the equation equal to zero or 
-52/3 + 3/2x +2 = 0.  Now you must isolate X to get the answer.  

1.  Subtract 3/2x from both sides of the equation.  
-54/3 +3/2x + 2 -3/2x = -3/2x

2.  Add the numbers on the left side of the equation together.  
-54/3 + 2/1 = -54/3 + 6/3 = -48/3

Now we have -48/3 = -3/2x

3.  Divide both sides of the equation by -3/2 to isolate the x.  
-48/3 * -2/3 = -3/2x / -3/2

Next we get 96/9 = X  

4.  Last reduce the fraction to get your answer.  

X = 32/3