Question 64205
f(x) = (x-3)/(x^2-16)

To find the domain we need to see which all values the function cannot take.

The given function is not defined when x^2 - 16 = 0
==> x^2 = 16
==> x = +4, -4

So domain = allreal numbers except 4, - 4.
==> D  = R - {4, -4}


Good Luck!!!