Question 734070
Please help me solve this problem:
log2 (x-1)+ log2 (x+3)=3
log2[ (x-1)(x+3)]=3
log2[(x-1)(x+3)]=log2(8)
(x-1)(x+3)=8
x^2+2x-3=8
x^2+2x-11=0
solve for x by quadratic formula:
x≈-4.4641 (reject, (x+3)>0)
or
x≈2.4641