Question 733891
Let the two consecutive integers be n, n+1.


three times the smaller integer = 3n
four times the larger integer = 4(n+1)


3n + 4(n+1) = 123
3n + 4n + 4 = 123
7n + 4 = 123
7n = 123 - 4 = 119
n = 119/7 =17


smaller integer is 17