Question 734019
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A way to use standard form of an ellipse is {{{(x-h)^2/(a^2-c^2)+(y-k)/(a^2)=1}}}.  Your description is an ellipse in standard position, so h and k are both 0.  Your description also makes a=4 and c=3, so your b^2 is {{{4^2-3^2=7}}}.  Be aware that this ellipse has major axis parallel or coinciding with the vertical coordinate axis, so "a" is in the denominator for the "y" rational expression.


The ellipse described is {{{x^2/7+y^2/16=1}}}.

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