Question 733905
{{{y = mx+b}}}


{{{y = (-3)x+b}}} ... plug in the given slope


{{{-2 = (-3)(1)+b}}} ... plug in the given point


{{{-2 = -3+b}}}


{{{-2+3 = b}}}


{{{1 = b}}}


{{{b = 1}}}


So the equation of the line is {{{y = -3x+1}}}