Question 733900
{{{y = mx+b}}}


{{{y = (2/3)x+b}}} Plug in the given slope m = 2/3


{{{-2 = (2/3)(6)+b}}} Plug in x = 6 and y = -2 (from the given point (6,-2))


The goal now is to solve for b.


{{{-2 = 12/3+b}}}


{{{-2 = 4+b}}}


{{{-2-4 = b}}}


{{{-6 = b}}}


{{{b = -6}}}


So the equation of the line is {{{y = (2/3)x-6}}}