<PRE><B>Question 733600</B>
A cyclist and a jogger start in a town and want to end 12 miles away.
 The cyclists rate is 2xs the jogger. He arrives 1.2 hours before the jogger. What is the rate of the cyclist.

:
let r = rate of the jogger
then
2r = rate of the cyclist
:
Write a time equation: time = dist/rate
:
jogger time - cyclist time = 1.2 hr
{{{12/r}}} - {{{12/(2r)}}} = 1.2
reduce the fraction
{{{12/r}}} - {{{6/r}}} = 1.2
multiply by r
12 - 6 = 1.2r
6 = 1.2r
r = 6/1.2
r = 5 mph rate of the jogger
then
2(5) = 10 mph rate of the cyclist
:
:
check this; find the actual time of each
12/5 = 2.4 hrs
12/10= 1.2 hrs
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differ: 1.2 hrs</PRE>