Question 64188
{{{(2x^4y^0 /z^2)- 5 }}}
but any number to the zeroth power is 1 so
={{{(2x^4 /z^2)- 5 }}} 


{{{(152x^7y^2 )/ (150x^9y)}}}
={{{(152y )/ (150x^2)}}}
={{{(76y )/ (75x^2)}}}


5,754,000,000 
=5.754 x 1 000 000 000
={{{5.754 * 10^9}}}