Question 733621
Sin(theta)=(1/5) and theta is in the second quadrant, find the remaining five trigonometric function values
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let O=opposite side
let A=adjacent side
let H=hypotenuse
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sin(x)=1/5=O/H (in Q2)
O=1, H=5
A=-√(H^2-O^2)=-√(25-1)=-√24
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Trig Functions:
sin(x)=O/H=1/5
cos(x)=A/H=-√24/5
tan(x)=O/A=-1/√24
csc(x)=H/O=5
sec(x)=H/A=-5/√24
cot(x)=A/O=-√24

Note: In Q2, sin>0, cos<0, tan<0