Question 733416

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(3,6\right)]. So this means that {{{x[1]=3}}} and {{{y[1]=6}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-6,0\right)].  So this means that {{{x[2]=-6}}} and {{{y[2]=0}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(0-6)/(-6-3)}}} Plug in {{{y[2]=0}}}, {{{y[1]=6}}}, {{{x[2]=-6}}}, and {{{x[1]=3}}}



{{{m=(-6)/(-6-3)}}} Subtract {{{6}}} from {{{0}}} to get {{{-6}}}



{{{m=(-6)/(-9)}}} Subtract {{{3}}} from {{{-6}}} to get {{{-9}}}



{{{m=2/3}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(3,6\right)] and *[Tex \LARGE \left(-6,0\right)] is {{{m=2/3}}}