Question 733364
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If the lead coefficient is negative, first take -1 out.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -1(6x^2\ -\ 13x\ +\ 2)]


Multiply the lead coefficient by the constant term:  6 times 2 is 12.


List the possible factor pairs for the product of the lead coefficient and the constant term:


1 and 12


2 and 6


3 and 4


-1 and -12


-2 and -6


-3 and -4



Add each of the pairs to see if you can find a sum that is equal to the 1st degree term, -13 in this case.  -1 and -12 works.  Split the 1st degree term:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -1(6x^2\ -\ 12x\ -\ x\ +\ 2)]


Divide the polynomial into the sum of two binomials.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -1\{(6x^2\ -\ 12x)\ -\ (x\ -\ 2)\}]


Factor any common factors from each of the binomials:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -1\{6x(x\ -\ 2)\ -\ 1(x\ -\ 2)\}]


Factor out the binomials:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -(6x\ -\ 1)(x\ -\ 2)]


Do the other one the same way.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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