Question 733273
Area  of any sector of circle  

{{{A=(n/360)pi*r^2}}} where {{{n}}} is the number of degrees in the central angle of the sector

Area of a sector {{{theta=110}}} degrees  and {{{r=15in}}} will be:

{{{A=(110/360)pi*(15in)^2}}}

{{{A=(0.30555555555555555555555555555556)pi*225in^2}}}

{{{A=(0.30555555555555555555555555555556)pi*225in^2}}}

{{{A=68.75pi*in^2}}}

{{{A=68.75*3.14*in^2}}}

{{{A=215.875in^2}}}