Question 733129
Solve each equation symbolically.
 A. (X+3)^2=7
 B. (X-2)^2-8=13

symbolically means using the quadratic formula

{{{(x+3)^2=7}}}


{{{x^2+6x+9=7}}}


{{{x^2+6x+2=0}}}

compare this equation with ax^2+bx+c

a=1, b=6, c=2

b^2-4ac=	36	-8					
b^2-4ac=	28							
{{{	sqrt(	28	)=	5.29	}}}			
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}								
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}								
x1=(	-6	+	5.29	)/	2			
x1=	-0.35							
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}								
x2=(	-6	-5.29	) /	2				
x2=	-5.65							

two values of x. -0.35 & -5.65