Question 732827
Imagine starting with 10.  Subtract 3/5 and count this as having found 1 of 3/5. Subtract another 3/5 from what has remained  and count this as having found another 3/5.  How much still remains?  Enough to keep subtracting 3/5 again?  


Now, instead of using repeated subtraction to count how many of 3/5 can be found in the number, 10, try something more economical:  DIVISION.


Divide 10 by 3/5.  THAT will be how many 3/5 is in 10.


10÷(3/5)=
{{{10/(3/5)=10*(5/3)}}}, because division by a fraction is the same as multiply by the reciprocal of the fraction,
={{{(10*5)/3}}}
={{{50/3=16&2/3}}}