Question 732707
{{{f (pi/2)= cos (2*theta) + sin( theta)}}}

{{{f (pi/2)=cos (2(pi/2))+ sin (pi/2)}}}

{{{f (pi/2)=cos (cross(2)(pi/cross(2)))+ sin (pi/2)}}}

{{{f (pi/2)=cos (pi)+ sin (pi/2)}}}

{{{f (pi/2)=cos (3.14)+ sin (3.14/2)}}}

{{{f (pi/2)=cos (3.14)+ sin (1.57)}}}

{{{f (pi/2)=-0.99999873+ 0.999999683}}}


{{{f (pi/2)=0}}}

answer: 4){{{ 0 }}}