Question 732621
the vertex of the quadratic function g(x)is located at (-2,-20). An x-intercept of g(x)is located at (-4,0). What is the y-intercept?
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Plot those 2 points.
Looks like the the parabola is opening up.
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Form:
4p(y-k) = (x-h)^2
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Substitute for x,y,h,k and solve for "p":
4p(0--20) = (-4--2)^2
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80p = (4)
p = 1/20
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Equation:
(1/5)(y+20) = (x+2)^2
y+20 = (5)(x+2)^2
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y-intercept ?
Let x = 0,
then y+20 = (20)
y = 0
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Cheers,
Stan H.
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