<PRE><B>Question 732606</B>
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There are 5 ways to choose the required 1 boy.  Then, for each of those 5 ways, there are 4 ways to choose the required 1 girl.  Then for each of those 20 ways, there remain 7 people, so 7 ways to choose the third committee member, and finally 6 ways to choose the fourth committee member.  Altogether, 5 times 4 times 7 times 6.  You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
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