Question 732374
Write the standard equation for the parabola with the given set of characteristics. Then graph the parabola 
axis of symmetry: y=0
focus: (4,0)
vertex: (0,0)
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This is a parabola that opens rightward:
Its basic equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of vertex
For given parabola:
p=4 (distance from vertex to focus on the axis of symmetry)
4p=16
Equation: y^2=16x

see graph below as a visual check:
{{{ graph( 300, 200, -6, 5, -10, 10, 4x^.5,-4x^.5) }}}