Question 732265
the steps in putting this equation into slope-intercpt form: 

{{{8x = 5-2y}}} ....solve for {{{y}}}


{{{8x +2y= 5-2y+2y}}}


{{{8x +2y= 5-cross(2y)+cross(2y)}}}


{{{8x-8x +2y= -8x+5}}}


{{{cross(8x)-cross(8x) +2y= -8x+5}}}


{{{2y= -8x+5}}}


{{{2y/2= -(8/2)x+5/2}}}


{{{y= -4x+2.5}}}........{{{slope-intercept}}} form, slope is {{{m=-4}}} and {{{y-intercept=2.5}}}


{{{ drawing( 600, 600, -5, 5, -5, 5,circle(0,2.5,0.1),graph( 600, 600, -5, 5, -5, 5, -4x+2.5)) }}}