<PRE><B>Question 732143</B>
A train running between two towns arrives at its destination 10 minutes late when it 
goes 40 miles per hour and 16 minutes late when it goes 30 miles per hour. The 
distance between the two towns is.
***
x=on-time travel time
x+(1/6)=travel time at 40 mph
x+(4/15)=travel time at 30 mph
distance=travel time*speed
10 min=1/6 hr
16 min=16/60=4/15 hr
..
40(x+(1/6))=30(x+(4/15))
40x+40/6=30x+8
10x=8-40/6=48/6-40/6=8/6=4/3
x=4/30=2/15
40(x+(1/6))=40*.3=12
or
30(x+(4/15))=30*6/15=12

distance between the two towns is=12 mi </PRE>