Question 732106
click here...<a href='http://www.mathway.com/answer.aspx?p=calg?p=2xSMB01x-(4-2x)?p=1?p=?p=?p=?p=?p=0?p=?p=0?p=?p=?p=SolveSMB15theSMB15EquationSMB15forSMB15x' target='_blank'><img src='http://www.mathway.com/math_image.aspx?p=2xSMB01x-(4-2x)?p=110?p=22' border='0' style='vertical-align:middle' alt='Click Here to Solve the Equation for x' /></a>...click here