Question 732070
{{{drawing(250,250,-1,10,-1,10,
locate(0,0,B),locate(9,0,C),locate(3.5,9.9,A),locate(4.5,0,9),locate(6.5,5,11),
locate(.7,5,10),
triangle(0,0,9,0,10/3,9.428090416) )}}}
<pre>
The largest side is opposite the largest angle.

The largest side is AC which is 11.
The angle opposite AC is &#8736;B (which you may give as &#8736;ABC or as &#8736;CBA)

That may be all you are asked to find. But in case you have
studied the law of cosines, I will continue to find the measure of
&#8736;B just in case:

To find the measure of &#8736;B we use the law of cosines:

cos(&#8736;B) = {{{(a^2+c^2-b^2)/(2ac)}}}

cos(&#8736;B) = {{{(9^2+10^2-11^2)/(2*9*10)}}}

cos(&#8736;B) = {{{(81+100-121)/180}}} 

cos(&#8736;B) = {{{60/180}}}

cos(&#8736;B) = {{{1/3}}} 

Use the inverse cosine feature of your calculator:

m&#8736;B = 70.52877937°

Edwin</pre>