Question 731932
Factor out a 6:  6(x^3 + 8)<P>
Inside the parentheses is now the sum of two cubes (8=2^3).<P>
(a^3 + b^3) = (a+b)(a^2 -ab + b^2).<P>
a=x and b=2 <P>
6((x+2)(x^2 -2x  +4))
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