Question 64095
<pre><font size = 5><b>what would be the domain of this equation: 
The square root of 9-4x. All is included under the 
radical! thanks

           ______
          <font face = "symbol">Ö</font>9 - 4x

An even root, such as square root, 4th root, 6th root,
etc. (BUT NOT an odd root, such as cube root, 5th 
root, 7th root, etc) gives a real result when and only 
when its radicand (what's under the radical) is not 
negative, that is, greater than or equal to 0.

This is an even root, so for the domain we must require
that its radicand be greater than or equal to 0:

         9 - 4x <font face = "symbol">³</font> 0

            -4x <font face = "symbol">³</font> -9

              x <font face = "symbol">£</font> 9/4

Graph of domain on a number line:


< =========================<font face = "symbol">·</font>--------
                          9/4

Domain in set builder notation {x|x <font face = "symbol">£</font> 9/4}

Domain in interval notation:  (-<font face = "symbol">¥</font>, 9/4] 


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Note: if it were an odd root instead of an 
even root the domain would always be

(-<font face = "symbol">¥</font>, <font face = "symbol">¥</font>)

Edwin</pre>