Question 731797
Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. 
-1, -3, 0; f(-2) = -8 
I have tried this: 
(x+1)(x+3)(x+0)
=(x+0)(x^2+4x+3)
=x^3+4x^2+3x 
then 
f(-8)=a(-2+1)(-2+3)(-2+0)  ************ f(-2), not f(-8)
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f(-2) = -8 + 16 - 6 = 2
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--> (-3)*(x^3+4x^2+3x)
f(x) = -3x^3 - 12x^2 - 9x