Question 731712
Y=-x+5.......................(1)
-5x+2y=10.....................(2)

Find the x & y intercept points by plugging x=0,y=0 in both equations.								
equation I								
when x=	0	y=	5	,(	0	,	5	)
when y =	0	x=	5	,(	5	,	0	)
Equation 2								
when x=	0	y=	5	(	0	,	5	)
when y =	0	x=	-2	(	-2	,	0	)
								
{{{drawing(300,300,-10,10,-10,10,grid(1),circle(0,5,0.3),circle(5,0,0.3),circle(0,5,0.3),circle(-2,0,0.3),graph(300,300,-10,10,-10,10,y=-x+5,y=(5/2)x+5))}}}								
								
You will observe that the point of intersection is						0	,	5
The solution of the system is			(  	0	,	5	)