Question 731667
{{{(x+3 )/ (x+5) + 6 / (x^2+3x-10)}}}.....factor {{{(x^2+3x-10)}}}...write {{{3x}}} as {{{5x-2x}}}


{{{(x+3 )/ (x+5) + 6 / (x^2+5x-2x-10)}}}...group


{{{(x+3 )/ (x+5) + 6 / ((x^2+5x)-(2x+10))}}}


{{{(x+3 )/ (x+5) + 6 / (x(x+5)-2(x+5))}}}


{{{(x+3 )/ (x+5) + 6 / ((x-2)(x+5))}}}....common denominator 


{{{(((x+3 )(x-2)) + 6) / ((x-2)(x+5))}}}


{{{(x^2-2x+3x-6 + 6) / ((x-2)(x+5))}}}


{{{(x^2+x) / ((x-2)(x+5))}}}


{{{x(x+1) / ((x-2)(x+5))}}}

since denominator cannot be equal to zero, we will find solutions if we set numerator equal to zero

{{{x(x+1)=0}}}

solutions:

{{{x=0}}}

and

{{{x+1=0}}}...=>...{{{x=-1}}}