Question 731655
Use the general rule:
{{{ ( a^b )^c = a ^(b*c) }}}
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{{{ ( 3a^2*b^3*c^(-2) ) / ( ( a^-1b^2c )^3 ) }}}
{{{ ( 3a^2*b^3*c^(-2) ) / ( a^(-3)*b^6*c^3 ) }}}
{{{ 3*( a^2 / a^(-3) )*( b^3 / b^6 )*( c^(-2) / c^3 ) }}}
{{{ 3*a^5*b^(-3)*c^(-5) }}}