Question 731655
{{{ (3a^2b^3c^-2)/(a^-1b^2c)^3  }}}....first eliminate negative exponents; {{{c^-2=1/c^2}}} and {{{a^-1=1/a}}}


{{{ (3a^2b^3(1/c^2))/((1/a)b^2c)^3  }}}


{{{ ((3a^2b^3)/c^2)/(b^2c/a)^3  }}}


{{{ ((3a^2b^3)/c^2)/((b^2c)^3/(a)^3)  }}}


{{{ ((3a^2b^3)/c^2)/((b^6c^3)/a^3)  }}}


{{{ (3a^2b^3a^3)/(c^2b^6c^3)  }}}


{{{ (3a^5b^3)/(c^5b^6)  }}}


{{{ (3a^5cross(b^3))/(c^5b^cross(6)^3)  }}}


{{{ (3a^5)/(b^3c^5)  }}}