Question 731648
{{{4x-3<2-x}}}...here you have an inequality...first add {{{x}}} to both sides

{{{4x+x-3<2-x+x}}}....cancel {{{-x}}} and {{{x}}} on the right side

{{{4x+x-3<2-cross(x)+cross(x)}}}

{{{5x-3<2}}}.....add {{{3}}} to both sides

{{{5x-3+3<2+3}}}...cancel {{{-3}}} and {{{3}}} on the left side

{{{5x-cross(3)+cross(3)<5}}}

{{{5x<5}}}

{{{x<5/5}}}

{{{x<1}}}

so, solutions for this inequality are all real numbers less than {{{1}}}

or

({{{-infinity}}},{{{1}}})

{{{ graph( 300, 200, -6, 5, -10, 10, x<1) }}} 

{{{cartoon( 
  number_line( 600, -10, 10, A=-10, B=1 ),number_line( 600, -10, 10, A=-9, B=1 ),number_line( 600, -10, 10, A=-8, B=1 ),number_line( 600, -10, 10, A=-3, B=1 ) ,number_line( 600, -10, 10, A=-2, B=1 ),number_line( 600, -10, 10, A=-1, B=1 ) ,number_line( 600, -10, 10, A=0.9, B=1 )    
    )}}}