Question 64034
suppose $x is invested at 14% annual interest
 interest after 1 year = $(14x)/100
 
rest $(12000-x)at 10% annual interest
 interest after 1 year =$(12000-x)10/100
  
  by the problem 14x/100 + (12000-x)10/100 =1632
             or   14x/100 +  1200 -10x/100 =1632
             or   4x/100=1632-1200=432
             or   x/25=432
             or   x=432*25= 10800

ans: $10800 is invested at 14%
     $(12000-10800)=$1200  is invested at 10%