Question 730930
What is the centre and radius of the circle with the equation 
2x^2+2y-12x+4y-15=0
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Standard form of equation for a circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius
For given equation:
2x^2+2y-12x+4y-15=0
This is not an equation of a circle because the y^2 term is missing.
Looks like a typing error, one of the y-terms should probably be squared.