Question 730735
If you draw this triangle you'll see that the hypotenuse is the side between the points (8,4) and (4,2).<P>
The length of the first leg is 4, the distance between (4,2) and (8,2).<P>
The length of the second leg is 2, the distance between (8,2) and (8,4)<P>
Pythagorean theorem shows the hypotenuse is:  {{{a^2 + b^2 = c^2 = 4^2 + 2^2 = c^2 = 16+40 = 20}}}<P>
c, the hypotenuse = {{{sqrt(20) = 2*sqrt(5)}}}<P>
The distance formula gives the same answer.  Find the distance between (4,2) and (8,4)<P>
d = {{{sqrt((y2-y1)^2 + (x2-x1)^2) = sqrt (4^2 + 2^2) = 2*sqrt(5)}}}
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