Question 730420
The ability of steel rod material to carry a load is related to the
 cross-sectional area of the rod.
 you can rewrite the expression that relates to the cross-sectional
 area of the steel rod to the desired tension:
(π (d^2))/4= (L)/(15,000 psi )
where d is the diameter of the steel rod in inches
and L is the load desired to be supported under tension, in pounds
 (L is divided by the safe working stress for medium steel rod, 15,000psi)
{{{(pi*d^2)/4}}} = {{{L/15000}}}
a. using the equation above, isolate the variable d to find an equation
 for the diameter of a steel rod needed for any load L.
Cross multiply
{{{15000*pi*d^2}}} = 4L
{{{d^2}}} = {{{(4L)/(15000*pi)}}}
:
d = {{{sqrt((4L)/(15000*pi))}}}
:
b. draw a graph of your equation for loads from 0 to 100,000 pounds.
Graph: y = {{{sqrt((4x)/(15000*pi))}}}
looks like this
{{{ graph( 300, 200, -10000, 100000, -2, 4, sqrt((4x)/(15000*pi))) }}}
c. Is this graph linear or nonlinear? You can answer that from this graph