Question 730616
Find an equation for the line that passes through (0,-5) and is perpendicular to the graph of x+3y=4. Write in Slope-Intercept form:
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Find the slope of the line.
x+3y=4
Solve for y

y = (-1/3)x + 4/3
The slope = -1/3
The slope of lines perpendicular is the negative inverse = 3
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(0,-5) is b, the y-intercept
--> y = 3x - 5