Question 730543
x sqrd/49-y sqrd/81=1, what are the slopes of the asymptotes?
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x^2/49-y^2/81=1
This is an equation of a hyperbola with horizontal transverse axis.
Its standard form of equation: {{{(x-h)^2/a^2-(y-k)^2/b^2=1}}}
slopes of hyperbolas with horizontal transverse axis=±b/a
For given equation:
a^2=49
a=7
b^2=81
b=9
slopes=±b/a=±9/7
..
Notes: 
Slopes of hyperbolas with vertical transverse axis=±a/b
Equations of asymptotes are straight lines that go thru the center of the hyperbola