<PRE><B>Question 730328</B>
 If two cars start from 92 miles apart and travel directly towards each other,
 and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles
 per hour faster, and they meet up at noon, what is the average speed of each car?
:
Let s = speed of the Car1
then
(s+6) = speed of Car2
;
The travel time of each car from the information given
Car 1: 1 hr, Car 2: 45 min or .75 hr
:
Write a distance equation: dist = time * speed
:
Car 1 dist + Car 2 dist = 92 mi
1s + .75(s+6) = 92
s + .75s + 4.5 = 92
1.75s = 92 - 4.5
s = {{{87.5/1.75}}}
s = 50 mph is the speed of Car 1
then, obviously
56 mph is the speed of car 2
:
:
:
Check this by finding the actual distance each car went
1*50 = 50 mi
.75*56 = 42 mi
----------------
total dist: 92 mi</PRE>