Question 730305
solve the following equation by using properties of logarithms: 4e^(3x)+1=17 
4e^(3x)+1=17
4e^(3x)=16
e^(3x)=4
3xlne=ln4
lne=1 (log of base=1)
3x=ln4
x=ln4/3
x≈0.4621..