<PRE><B>Question 730348</B>
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Your first problem is just a bunch of arithmetic. You can do your own arithmetic.


Calculate the first 11 perfect cubes, 1 cubed, 2 cubed, 3 cubed...and so on.  Stop at 11 because 12 cubed is larger than 1600.  Divide each of these perfect cubes into 1600.  Count the number of them that divide 1600 evenly.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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