<PRE><B>Question 730322</B>
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I don&#39;t know what &quot;The surace area of a spere&quot; is, but the &lt;i&gt;&lt;b&gt;surface&lt;/b&gt;&lt;/i&gt; area of a &lt;i&gt;&lt;b&gt;sphere&lt;/b&gt;&lt;/i&gt; is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ 4\pi{r^2}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4\pi{r^2}\ =\ 676\pi]


Solve for the radius, *[tex \LARGE r], and then double it to get the diameter.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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