Question 730327
Equation of a circle whose center is at ({{{h}}},{{{k}}}) is:

{{{(x-h)^2+(y-k)^2=r^2}}}....This referrers to  the "center-radius form". It may also be referred to as "standard form".

given:

 center is at ({{{h}}},{{{k}}}) = ({{{-2}}},{{{-1}}}) 

and {{{r=2sqrt(3)}}}

plug given values in formula


{{{(x-(-2))^2+(y-(-1))^2=(2sqrt(3))^2}}}


{{{(x+2)^2+(y+1)^2=4*3}}}


{{{(x+2)^2+(y+1)^2=12}}}


{{{drawing( 600, 600, -7, 7, -7, 7,grid(1),circle(-2,-1,0.1),circle(-2,-1,3.464),graph( 600, 600, -7, 7, -7, 7 )))}}}